Question

Question #3ee3e

Answer 1

`["Ne"]3s^2 3p^5`

Explanation:

Shorthand electronic configurations are written with the symbol of noble gas having the closest lowest atomic number.
In this case, it's Neon (Ne).

A chlorine atom has 17 electrons. Neon has 10. So, the electronic configuration will be in the form [Ne] (something) . And [Ne] represents 10 core electrons.

Electronic configurations are written as `1s^2 2s^2 2p^6 3s^2 3p^6`. Where the superscripts are the maximum electrons in that orbit.

STEP 1: For Chlorine, the first 10 (core) electrons can be written as `color(blue)(1s^2 2s^2 2p^6` (which is the electronic configuration of Neon, obviously).

STEP 2: Now we can divide the rest seven electrons in into two orbits - `color(red)(3s " & " 3p`.
Since 3s can hold only 2 electrons, the rest 5 will go to 3p.

Step 3: So,the electronic configuration of Chlorine atom would be `color(blue)(1s^2 2s^2 2p^6) color(red)( 3s^2 3p^5`

STEP 4: Now, after substituting `color(blue)(1s^2 2s^2 2p^6` for `color(blue)(["Ne"]`, the shorthand electronic configuration of Chlorine atom would be
`color(blue)(["Ne"]color(red)(3s^2 3p^5`.

Hope that helps!