Question

What is the perimeter of a triangle with corners at `(2 ,6 )`, `(4 ,2 )`, and `(3 ,1 )`?

Answer 1

Perimeter `=10.985`

Explanation:

Let A(2,6), B(4,2) & C(3,1) be the vertices and their coordinates.
`AB=sqrt((4-2)^2+(2-6)^2)=sqrt(2^2+4^2)=2sqrt5`
`BC=sqrt((3-4)^2+(1-2)^2)=sqrt2`
`CA=sqrt((2-3)^2+(6-1)^2)=sqrt(1+25)=sqrt26`
Perimeter `=AB+BC+CA=2sqrt5+sqrt2+sqrt26`
Perimeter`=4.472+1.414+5.099=10.985`