Question

How do you factor out the greatest common factor of `8x ( z + 13) + ( z + 13)`?

Answer 1

`(z+13)(8x+1)`

Explanation:

`8z(z+13)+(z+13)`

let`" "u=z+13`

we have

`8xu+u`

factorise

u(8x+1)#

substitue back

`(z+13)(8x+1)`

in other words we have a bracket ie `(z+13)`

as the gcf.