Question #6f7cd
1 Answer
Oct 3, 2017
The Rayleigh criterion for diffraction-limited vision for the minimum resolvable detail of objects located at a distance
#sintheta_D=1.22lambda/theta_D#
Inserting given values we get
We know that for very small value of
#sintheta~~theta#
#=>theta~~2.44xx10^-4" radian"#
#a=thetaxxD#
Inserting calculated and given values we get
#a=(2.44xx10^-4)xx(10xx10^3)=2.44" m"#