How do you solve #3(12x+12)=6(4+5x)#?

1 Answer
Jim G.
Oct 4, 2017

#x=-2#

Explanation:

#"distribute the brackets on both sides of the equation"#

#36x+36=24+30x#

#"collect term in x on the left side and numeric values on"#
#"the right side"#

#"subtract 30x from both sides"#

#36x-30x+36=24cancel(+30x)cancel(-30x)#

#rArr6x+36=24#

#"subtract 36 from both sides"#

#6xcancel(+36)cancel(-36)=24-36#

#rArr6x=-12#

#"divide both sides by 6"#

#(cancel(6) x)/cancel(6)=(-12)/6#

#rArrx=-2#

#color(blue)"As a check"#

Substitute this value into the equation and if both sides are equal then it is the solution.

#"left "=3(-24+12)=3xx-12=-36#

#"right "=6(4-10)=6xx-6=-36#

#rArrx=-2" is the solution"#

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