How do you solve #\frac { 6} { 9} = \frac { b } { 3}#?

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Answer 1 · 2017-10-04T19:03:42

See a solution process below:

Multiply each side of the equation by #color(red)(3)# to solve for #b# while keeping the equation balanced:

#color(red)(3) xx 6/9 = color(red)(3) xx b/3#

#18/9 = cancel(color(red)(3)) xx b/color(red)(cancel(color(black)(3)))#

#18/9 = b#

#2 = b#

#b = 2#

Another approach is to first simplify the fraction on the left:

#(3 xx 2)/(3 xx 3) = b/3#

#(color(red)(cancel(color(black)(3)))xx 2)/(color(red)(cancel(color(black)(3)))xx 3) = b/3#

#2/3 = b/3#

#2 = b#

#b = 2#