How do you solve # 10x + 16= 6x - 8 #?

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Answer 1 · 2017-10-05T19:27:42

See a solution process below:

First, subtract #color(red)(16)# and #color(blue)(6x)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#-color(blue)(6x) + 10x + 16 - color(red)(16) = -color(blue)(6x) + 6x - 8 - color(red)(16)#

#(-color(blue)(6) + 10)x + 0 = 0 - 24#

#4x = -24#

Now, divide each side of the equation by #color(red)(4)# to solve for #x# while keeping the equation balanced:

#(4x)/color(red)(4) = -24/color(red)(4)#

#(color(red)(cancel(color(black)(4)))x)/cancel(color(red)(4)) = -6#

#x = -6#

Answer 2 · 2017-10-05T19:28:22

#x=color(purple)(-4)#

#10x+16=6x-8#
Transfer x terms to the left and constant (number) terms to the right.
#10x-6x=-16-8#
#4x=-24#
#x=-24/4=color(purple)(-4)#