Question

The height from which the body is released is numerically equal to the velocity accquired find the that height is equal to ? Ans:2g

Answer 1

This is just algebra, but isn't simple...

Explanation:

Due to conservation of energy, `E_p` lost = `E_k` gained

So `m.g.h = 1/2mv^2`

So `g.h = 1/2v^2`

Or 2g.h = v^2

If we say v = h then substitute that into the previous equation,

`2g.h = h^2`

So dividing both sides by h get us

2g = h

That means if we drop an object of any mass from 19.82 m it will hit the ground at 19.82 m/s.