How do you evaluate # ( 4+ 3} / { 4^ { 2} + 4- 6}#?

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Answer 1 · 2017-10-06T22:27:01

#0.5 or 1/2#

The giant bar can be rewritten as a division sign with parentheses.

So your question is the same as:

#(4+3)-:(4^2+4-6)#

Use order of operations:
Parentheses
Exponents
Multiplication
Division
Addition
Subtraction

First parentheses:

#7-:(4^2+4-6)#

This second set of parentheses has exponents, so we do that first before the addition and subtraction:

#7-:(16+4-6)=7-:(20-6)=7-:(14)#

Finally we finish with division:

#7-:14=1/2=0.5#

Answer 2 · 2017-10-06T22:27:20

#1/2#

It's best to evaluate the top and bottom separately:

The numerator is #7#

The denominator is #16+4-6 = 14#

So your difficult looking fraction is nothing more than #7/14#, which if you reduce, is equivalent to #1/2#.