Question

What volume (in mL) of 9.91 M sodium chloride is required to produce 100.0 mL of a 0.398M solution?

Answer 1

`4.02 mL`

Explanation:

Recall that molarity and volume can be expressed in the following ratio:

`V_1M_1 = V_2M_2`

So all you have to do is plug in your values:

`V_1 * 9.91 M = 100 mL * 0.398 M`

Solve for `V_1` to get:

`V_1 = (100 mL * 0.398 M) / (9.91 M) = 4.016 mL`

With significant figures, you get a final answer of `4.02 mL`.