Question

How do you solve `(x+2)/6=(x-1)/12`?

Answer 1

`x=-5`

Explanation:

By cross multiplication,
`12(x+2)=6(x-1)`
`12x+24=6x-6`
`12x-6x=-24-6`
`6x=-30`
Divide both sides by `color(red)(6)`
`cancel(6x)/cancelcolor(red)(6) = (-30)/color(red)(6)`
`x=-5`