How do you solve this system of equations: #y+ 2y = - 1 and 4x + 5y = - 10#?

1 Answer
Oct 9, 2017

#x=-25/12# and #y=-1/3#

Explanation:

First we can find y by add y together in #y+2y=-1#
#3y=-1# and #y=-1/3#

Now we have #y=-1/3# so we can substitute it into #4x+5y=-10# to find x

#4x+5(-1/3)=-10#
#4x-5/3=-10#
#4x=-25/3#
#x=-25/12#
You can check the solution by substitute x and y the second equation