(sin(10°)+sin(20°)+sin(40°)+sin(50°))/(cos(10°)+cos(20°)+cos(40°)+cos(50°)) = ?

2 Answers
Dee
Oct 9, 2017

#-6.405331191#

Explanation:

#(sin(10)+sin(20)+sin(40)+sin(50))/(cos(10)+cos(20)+cos(40)+cos(50))#
You need to punch in each term in a calculator, sum up the numerator and denominator separately, then divide the two sums.

P dilip_k
Oct 9, 2017

#(sin(10)+sin(20)+sin(40)+sin(50))/(cos(10)+cos(20)+cos(40)+cos(50))#

#=(sin(10)+sin(50)+sin(40)+sin(20))/(cos(10)+cos(50)+cos(40)+cos(20))#

#=(2sin(30)cos(20)+2sin(30)cos(10))/(2cos(30)cos(20)+2cos(30)cos(10))#

#=(2*1/2*cos(20)+2*1/2*cos(10))/(2*sqrt3/2*cos(20)+2*sqrt3/2*cos(10))#

#=(cos(20)+cos(10))/(sqrt3(cos(20)+cos(10)))=1/sqrt3#

Related questions
Impact of this question
22795 views around the world
You can reuse this answer
Creative Commons License