How do you solve #\frac{x^{2}-x-6}{x}=x-3#?

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Answer 1 · 2017-10-10T19:03:06

#x=3#

Start by multiplying by #x# on both sides:

#x^2-x-6=(x-3)x#

Distribute:

#x^2-x-6=x^2-3x#

Combine like terms:

#-6=-2x#

Divide both sides by #-2#

#x=3#