Question #b61ac

1 Answer
Oct 12, 2017

The limit does exist as x approaches 1.

Explanation:

Just because f(1) does not equal the limit does not mean that the limit does not exist as x approaches 1. The limit exists because the right hand limit as x approaches 1 equals the left hand limit as x approaches 1. In this case, the limit as x approaches 1 is 2.