Question #b61ac
1 Answer
Oct 12, 2017
The limit does exist as x approaches 1.
Explanation:
Just because f(1) does not equal the limit does not mean that the limit does not exist as x approaches 1. The limit exists because the right hand limit as x approaches 1 equals the left hand limit as x approaches 1. In this case, the limit as x approaches 1 is 2.