Question #6edb2

1 Answer
Somebody N.
Oct 12, 2017

#1#

Explanation:

For :
#(x-3e^-x)/(x+5e^-x)#
Rewriting as:

#(x-3/(e^x))/(x+5/(e^x))#

For limits to infinity we can disregard #3/(e^x)# and #5/(e^x)#since these will just limit to zero.

#(x)/(x)=1#

So:

#lim_(x->oo)((x-3e^-x)/(x+5e^-x))= 1#

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