How do you solve #3- 2x \geq - 3#?

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Answer 1 · 2017-10-12T14:00:55

#x<=3#

You're simply solving for x:

#color(blue)(3-) 2x-3 >= -3 color(blue)(- 3)#
Subtract 3 from both sides

#-2x>=-6#
Simplify

#(color(blue)(-1))-2x <= -6 (color(blue)(- 1))#
Multiply both sides by #-1# (this will reverse the inequality)

NOTE: Whenever multiplying or dividing by a negative value, always flip your inequality sign

#2x<=6#
Simplify

#(2x)/color(blue)(2) <= 6/color(blue)(2)#
Divide both sides by 2

#color(green)(x <= 3)#
Simplify once more, and you're done!