Question

Glucose is used as an energy source by the human body. The overall reaction in the body is described by the equation C6H12O6(aq) + 6O2(g) = 6CO2(g) + 6H2O(l). How many grams of oxygen are required to convert 28.0 g of glucose to CO2 and H2O?

Answer 1

28.1 grams to three significant figures.

Explanation:

Glucose `C_6H_12O_6` has a molecular mass of 180 grams.

`6 xx C = 6 xx 12 = 72`
`12 xx H = 12 xx 1 = 12`
`6 xx O = 6 xx 16 =96` adding these gives
180 grams per mole.

To find the number of moles divide 28.0 grams by 180. grams

`28.0/180 = .156`moles

It requires 6 moles of Oxygen to "burn" 1 mole of glucose. so to find the number of moles of Oxygen required multiply by 6

`.156 xx 6 = .936` moles of Oxygen required.

Oxygen has a molecular mass of 32

`2 xx O = 2 xx 16 = 32` grams per mole.

To find the number of grams of Oxygen multiple moles by grams per mole.

`.936 xx 32 = 28.1` grams Oxygen