Question

How do you solve `9^x=45`?

Answer 1

`x ~~ 1.73`

Explanation:

You can log both sides of the equation to bring `x` down.

`log 9^x = log45`
`x log 9 = log 45`
`x = log 45/log 9`
`x ~~ 1.73 rarr` to `3` s.f