How do you solve #(2h-6)/6 = 2/3#?

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Answer 1 · 2017-10-15T12:18:10

See a solution process below:

First, multiply each side of the equation by #color(red)(6)# to solve eliminate the fractions while keeping the equation balanced:

#color(red)(6) xx (2h - 6)/6 = color(red)(6) xx 2/3#

#cancel(color(red)(6)) xx (2h - 6)/color(red)(cancel(color(black)(6))) = cancel(color(red)(6))2 xx 2/color(red)(cancel(color(black)(3)))#

#2h - 6 = 4#

Next, add #color(red)(6)# to each side of the equation to isolate the #h# term while keeping the equation balanced:

#2h - 6 + color(red)(6) = 4 + color(red)(6)#

#2h - 0 = 10#

#2h = 10#

Now, divide each side of the equation by #color(red)(2)# to solve for #h# while keeping the equation balanced:

#(2h)/color(red)(2) = 10/color(red)(2)#

#(color(red)(cancel(color(black)(2)))h)/cancel(color(red)(2)) = 5#

#h = 5#