A triangle has corners at $(6 ,7 )$ , $(2 ,6 )$ , and $(1 ,5 )$ . How far is the triangle's centroid from the origin?

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Answer 1 · 2017-10-15T22:41:59

Distance between centroid and origin is
d = sqrt5 = 2.2361

Coordinates of centroid:
$x = (x1 + x2 + x3)/3, y = (y1 + y2 + y3)/3$

$x = (6+2+1)/3=3$
$y = (7+6+5)/3 = 2$
Coordinates of centroid of the triangle (1,2)#

Coordinates of origin (0,0).
Distance between centroid and origin is
$d = sqrt((1-0)^2+(2-0)^2) = sqrt5 = 2.2361$

A triangle has corners at (6 ,7 )(6 ,7 ), (2 ,6 )(2 ,6 ), and (1 ,5 )(1 ,5 ). How far is the triangle's centroid from the origin?