Question #89e4c
1 Answer
Oct 16, 2017
Explanation:
The energy of a photon can be expressed in terms of its wavelength by using a form of the Planck - Einstein relation.
#E =h * c/(lamda)#
Here
#E# is the energy of the photon#h# is Planck's constant, equal to#6.626 * 10^(-34)"J s"# #c# is the speed of light in a vacuum, usually given as#3 * 10^8"m s"^(-1)# #lamda# is the wavelength of the wave
So all you have to do here is to plug in the value you have for the wavelength of the photon and solve for
#E = 6.626 * 10^(-34)"J" color(red)(cancel(color(black)("s"))) * (3 * 10^8 color(red)(cancel(color(black)("m"))) color(red)(cancel(color(black)("s"^(-1)))))/(0.000046color(red)(cancel(color(black)("m"))))#
#E = color(darkgreen)(ul(color(black)(4.3 * 10^(-21)color(white)(.)"J")))#
The answer is rounded to two sig figs, the number of sig figs you have for the wavelength of the photon.