How do you solve #-9s = - 11s + 8#?

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Answer 1 · 2017-10-16T02:33:10

See a solution process below:

Step 1: Add #color(red)(11s)# to each side of the equation to isolate the #s# term while keeping the equation balanced:

#color(red)(11s) - 9s = color(red)(11s) - 11s + 8#

#(color(red)(11) - 9)s = 0 + 8#

#2s = 8#

Step 2: Divide each side of the equation by #color(red)(2)# to solve fr #s# while keeping the equation balanced:

#(2s)/color(red)(2) = 8/color(red)(2)#

#(color(red)(cancel(color(black)(2)))s)/cancel(color(red)(2)) = 4#

#s = 4#