Question

How do you solve `\frac{x^{2}-3x-28}{x}=x-7`?

Answer 1

`x=7`

Explanation:

Multiply both sides by `x` so you get rid of it as a denominator.

This will give you:
`x^2-3x-28=x(x-7)`
`x^2-3x-28=x^2-7x`

Move all the unknowns to one side and solve for `x`.
`x^2-x^2-3x+7x=28`
`cancel(x^2)-cancel(x^2)-3x+7x=28`
`4x=28`
`:.x=7`