How do you solve \frac{x^{2}-3x-28}{x}=x-7?

1 Answer
Oct 16, 2017

x=7

Explanation:

Multiply both sides by x so you get rid of it as a denominator.

This will give you:
x^2-3x-28=x(x-7)
x^2-3x-28=x^2-7x

Move all the unknowns to one side and solve for x.
x^2-x^2-3x+7x=28
cancel(x^2)-cancel(x^2)-3x+7x=28
4x=28
:.x=7