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Answer 1 · 2017-10-16T07:25:53

Jason can make #9# identical care packages with #5# packs of gums and #3 # lip balms in each.

To make each care package identical, we will find out the Highest common factor ( HCF ) of 45 and 27,

#45 = 5\times 3\times3\times 1#

and

#27 = 3\times3\times3\times 1#

So Highest common factor of 45 and 27 = # 3\times\3\times \1= 9#

Now,
#45/9 = 5# packs of gums

can be put together with

#27/9 =3 # lip balms

in order to make each care package identical.

Answer : Jason can make #9# identical care packages with #5# packs of gums and #3 # lip balms in each.