Question

How do I solve `(2^x)^x=10`?

Answer 1

`x approx +- 1.822616`

Explanation:

`(2^x)^x = 10`

`2^(x^2) =10`

`x^2 log_10 2= 1`

`x^2 = 1/log_10 2 approx 3.321928`

`x approx +- sqrt 3.321928`

`approx +- 1.822616`