How do you graph #y = 1/6(x + 12)#?

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Answer 1 · 2017-10-17T15:34:09

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For #x = 0#

#y = 1/6(0 + 12)#

#y = 1/6 * 12#

#y = 2# or #(0, 2)#

First Point: For #x = 6#

#y = 1/6(6 + 12)#

#y = 1/6 * 18#

#y = 3# or #(6, 3)#

We can next plot the two points on the coordinate plane:

graph{(x^2+(y-2)^2-0.025)((x-6)^2+(y-3)^2-0.025)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(6y - x - 12)(x^2+(y-2)^2-0.025)((x-6)^2+(y-3)^2-0.025)=0 [-10, 10, -5, 5]}