How do you solve #|x - 10| \leq 8#?

1 Answer
1s2s2p
Oct 18, 2017

#x<=18#

Explanation:

So, you take out the #abs()# part of the eqquation to get #x-10<=8#

By rearranging we get #x<=8+10 => x<=18#

However, as we are taking the modulus (absolute value) of #x-10#, then #x-10<=-8#

By rearranging we get #x<=-8+10 => x<=2#

The problem is, is that the modulus (absolute value) of a funtion is always positive, so it will always be more than #-8#, the only solution is #x<=18#

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