Question

There consecutive integers have a sum of 159, what are their values?

Answer 1

Here it is made clear that the numbers are integers, so they can't be fractional,
Let the smallest number be `x-1`
Then the middle number will be `x`
Then the largest number will be `x+1`
Then they add up to 159,
That means,
`x-cancel1+x+x+cancel1=159`
`3x=159`
`x=53`
That's the middle number
The smallest number will be `x-1=53-1=52`
The largest number will be `x+1=53+1=54`
The numbers are 52,53,54

Answer 2

The integers are 52, 53 and 54.

Explanation:

If the first integer in n then:

`n + (n+1) + (n+2)=159`

This gives:

`3n+3 = 159`, `3n = 156`

This gives `n=52`.

So the 3 consecutive integers are 52, 53 and 54.