Let #x# be the first odd integer. Then the next odd integer will be #2# greater than #x#, or #x+2#. We know that the sum of these two numbers is #36#, so we can write the equation:
#x+(x+2)=36#
#2x+2=36#
#2x=34#
#x=17#
This means that the first odd integer is #17#, and the other one is #17+2=19#.