Question #92aa1
1 Answer
Oct 19, 2017
vertex = (h,k) = (1,3)
focus = (h, (k+p)) = (1, 6)
directrix is y = k-p, y = 3 - 3 = 0
Explanation:
The standard form is
where focus is ( h, (k+p)),
directrix is y = k -p
vertex is (h,k)
Where h = 1, k = 3, p = 3
vertex = (h,k) = (1,3)
focus = (h, (k+p)) = (1, 6)
directrix is y = k-p, y = 3 - 3 = 0
graph{(1/12)(x-1)^2+3 [-10, 10, -5, 5]}