A particle travels 10m in 5sec and 10m in 5sec and 10m in 3sec assuming constant acceleration what is the distance travelled in next 2sec? Ans:8.3m

1 Answer
Soham C.
Oct 19, 2017

The distance traveled is 8.125m

Explanation:

#u1 = 10/5=2 # m/s ; #t1=8 s#

#v1= 20/8=2.5#m/s

#a= (v1-u1)/t=(2.5-2)/8=0.0625# m/#s^2#

#u2=v1=2.5#m/s ; #t2=10s#

#s=u2*t2+(0.5*at2^2) = 2.5*10+(0.5*0.0625*10*10)#
Therefore, #s=28.125 # m

The distance traveled #=28.125-20=8.125 # m

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