Solve for x: 2x-1=(6x^3-5x^2+3x)/(3x^2-x-14)?
1 Answer
Oct 19, 2017
Explanation:
Given:
2x-1 = (6x^3-5x^2+3x)/(3x^2-x-14)
Multiply both sides by
6x^3-5x^2+3x = (2x-1)(3x^2-x-14)
color(white)(6x^3-5x^2+3x) = 6x^3-5x^2-27x+14
Subtract
30x=14
Divide both sides by
x=14/30=7/15