Solve for x: 2x-1=(6x^3-5x^2+3x)/(3x^2-x-14)?

1 Answer
Oct 19, 2017

x=7/15

Explanation:

Given:

2x-1 = (6x^3-5x^2+3x)/(3x^2-x-14)

Multiply both sides by (3x^2-x-14) to find:

6x^3-5x^2+3x = (2x-1)(3x^2-x-14)

color(white)(6x^3-5x^2+3x) = 6x^3-5x^2-27x+14

Subtract 6x^3-5x^2-27x from both sides to get:

30x=14

Divide both sides by 30 to get:

x=14/30=7/15