Question

Question #3ed1f

Answer 1

`2e^(2x)`

Explanation:

...which you get by the chain rule. If `f(x) = v(u(x))`, then `(df)/(dx) = (dv)/(du) * (du)/(dx)`

So here, u(x) = 2x, and v= `e^u`, so `(dv)/(du) = e^u`, and `(du)/(dx) = 2`

Put it all together, and you have `2e^(2x)`

GOOD LUCK