How do you solve #3^x-2= 4^2#?

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Answer 1 · 2017-10-21T00:23:56

~ 2.631....

#3^x-2=4^2#

Add 2 to other side

#3^x=4^2+2#

Simplify

#3^x=18#

Take natural log (ln) of both sides

#ln(3)^x=ln(18)#

Use log properties to move x down

#xln(3) = ln(18)#

Divide by ln(3) to isolate x

#x=ln(18)/ln(3)#

Plug into calculator and solve

~ 2.631