What is the standard form of $y = (x^{2} - 4) (2 x - 10) + {(7 x + 3)}^{2}$ $y= (x^2-4)(2x-10) + (7x+3)^2$ ?

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What is the standard form of $y = (x^{2} - 4) (2 x - 10) + {(7 x + 3)}^{2}$ $y= (x^2-4)(2x-10) + (7x+3)^2$ ?

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Answer 1 · 2017-10-21T07:15:10

$y = 3 x^{3} + 39 x^{2} + 34 x + 49$ $y = 3x^3 +39x^2 +34x + 49$

Explanation:

Expand and simplify my dude, if you find expanding difficult refer to the distributive law.

$y = 3 x^{3} - 10 x^{2} - 8 x + 40 + 49 x^{2} + 42 x + 9$ $y = 3x^3 - 10x^2 - 8x + 40 + 49x^2 + 42x + 9$
$y = 3 x^{3} + 39 x^{2} + 34 x + 49$ $y = 3x^3 +39x^2 +34x + 49$

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What is the standard form of $y = (x^{2} - 4) (2 x - 10) + {(7 x + 3)}^{2}$ $y= (x^2-4)(2x-10) + (7x+3)^2$ ?

1 Answer

Explanation:

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What is the standard form of y= (x^2-4)(2x-10) + (7x+3)^2y=(x2−4)(2x−10)+(7x+3)2y= (x^2-4)(2x-10) + (7x+3)^2?

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Explanation:

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What is the standard form of $y = (x^{2} - 4) (2 x - 10) + {(7 x + 3)}^{2}$ $y= (x^2-4)(2x-10) + (7x+3)^2$ ?