Question

An object with a mass of `4 kg` is hanging from a spring with a constant of `3 (kg)/s^2`. If the spring is stretched by `13 m`, what is the net force on the object?

Answer 1

1 N downwards

Explanation:

Weight of object `= text(mg) = 4 text(kg) × 10 text(ms)^-2 = 40 text(N)` (downwards)

Spring Force `= text(kx) = 3 (text(kg))/text(s)^2 × 13 text(m) = 39 text(N)` (upwards)

`text(Net Force) = 40 text(N) - 39 text(N) = 1 text(N)` (downwards)