How do you write $2y+3=-1/3(x-2)$ in standard form?

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Answer 1 · 2017-10-21T13:03:31

First, standard form is $ax+by+c=0$
In this question, we can expend the formula and rearrange it.

You can try it first, and the steps are as follow:

Step 1: Expend it
$2y+3=-1/3x+2/3$

As there are fraction in the formula and it doesn't look good, we can eliminate it by multiplyng 3.

Step 2: Multiply by 3
$6y+9=-1x+2$

Step 3: Rearrange the terms
$x+6y+7=0$

And we can get the answer! :)

How do you write 2y+3=-1/3(x-2)2y+3=-1/3(x-2) in standard form?