Question #7f8b3

2 Answers
Oct 21, 2017

The answer is #1/5#.

Explanation:

#f'(x)=1/5* dx/dx+x *d(1/5)/dx+d(4/15)/dx#

The above is using product rule for #(1/5)(x)#.
And we know that differentiating a constant is #0#, so we can get the following:

#f'(x)=1/5*1+x*0+0#
#=1/5#

It's the answer!
Hope it can help you :)

Oct 21, 2017

#f'(x)=1/5#

Explanation:

The explanation is this:
#f'(x)=1/5*1 x^(1-1)+4/15*0x^(0-1)#
#f'(x)=1/5x^0+0*x^-1#
#f'(x)=1/5*1+0#
#f'(x)=1/5#

For more info (https://www.mathsisfun.com/calculus/derivatives-rules.html)