What is the derivative of $y = x^2 ln(2x)$ ?

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$y = x^2 ln(2x)$

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Answer 1 · 2017-10-22T04:53:30

see below.

$y=x^2ln(2x)$

$dy/dx=x^2d/dxln(2x)+ln(2x)d/dxx^2$

$=x^2(1/2x)d/dx2x+ln(2x)(2x)$

$=x/2*2+2xln(2x)$

$=x+2xln(2x)$