How do you differentiate #arctan(x/2)#? Calculus Differentiating Trigonometric Functions Differentiating Inverse Trigonometric Functions 1 Answer Manasvini Nittala Oct 22, 2017 #2/(x^2+4)# Explanation: #arctan(x/2)=tan^-1(x/2)# the derivative of #tan^-1(x/2)=1/(1+(x/2)^2)=1/(1+x^2/4)1/2=1/2(4/(4+x^2))=2/(4+x^2# Answer link Related questions What is the derivative of #f(x)=sin^-1(x)# ? What is the derivative of #f(x)=cos^-1(x)# ? What is the derivative of #f(x)=tan^-1(x)# ? What is the derivative of #f(x)=sec^-1(x)# ? What is the derivative of #f(x)=csc^-1(x)# ? What is the derivative of #f(x)=cot^-1(x)# ? What is the derivative of #f(x)=(cos^-1(x))/x# ? What is the derivative of #f(x)=tan^-1(e^x)# ? What is the derivative of #f(x)=cos^-1(x^3)# ? What is the derivative of #f(x)=ln(sin^-1(x))# ? See all questions in Differentiating Inverse Trigonometric Functions Impact of this question 1225 views around the world You can reuse this answer Creative Commons License