Question

If 100.0 mL of 0.426 M NaOH solution is diluted to 500.0 mL, what is the concentration of the diluted solution?

Answer 1

`C_2=0.0852*mol*L^-1`

Explanation:

Because the number of moles contained in the solution are CONSTANT, then upon dilution....

`C_1V_1=C_2V_2`....

And so...`C_2=(C_1V_1)/(V_2)=(100.0*mLxx0.426*mol*L^-1)/(500*mL)=??*mol*L^-1`