What is a quadratic equation having roots #\sqrt 7 and -\sqrt 7#?

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Answer 1 · 2017-10-23T13:02:23

#x^2 = 7#

#sqrt7 and -sqrt7#

Step by step!

#x = sqrt7 and x = -sqrt7#

#x -sqrt7 = 0 and x + sqrt7 = 0#

#(x - sqrt7) (x + sqrt7) = 0#

#x^2 + xsqrt7 -xsqrt7 - 7 = 0#

#x^2 + 0 - 7 = 0#

#x^2 - 7 = 0#

#x^2 = 7 -> "Equation"#

Proof..

#x^2 = 7#

#x = +-sqrt7#

#x = +sqrt7 or -sqrt 7#