Solve for #x#, given #3 log^2 (x-1) - 10 log (x-1) = -3#?
1 Answer
Oct 23, 2017
See explanation.
Explanation:
We can solve this equation by frst substituting
#t=log(x-1)#
The equation turns into:
#3t^2-10t+3=0#
To solve the equation we use the quadratic formula:
#Delta=b^2-4ac#
#Delta=(-10)^2-4*3*3#
#Delta=100-36=64#
#sqrt(Delta)=8#
Now we have to calculate the values of
Answer:
The equation has