How do you solve #6x + 4= 4( 3/ 2x + 1)#?

2 Answers
Oct 24, 2017

Correcting the equations as
#color(red)(6x + 4 = 4*((3/2)x + 1))#

#x = -1#

Explanation:

Remove the brackets first.
#6x + 4 = 4*(3/2)*x +4#
#6x + 4 = 6x + 4#

As the LHS & RHS are same, this cannot be solved.

By changing the coefficient of x in RHS, we will try to solve.

Correct the given equation as
#6x + 4 = 4(color(red)(3/4)x + 1)#

Removing brackets,
#6x + 4 =cancel( 4)*(3/cancel(4))*x +1#
#6x + 4 = 3x + 1#

Bringing x terms to LHS & constants to RHS,

#6x - 3x = 1 - 4#
#3x = -3#
# x = -1#

Oct 24, 2017

All real numbers are solutions.

Explanation:

#6x + 4 = 4(3/2 x +1)#
Use the distributive property.
#6x + 4 = (4)(3/2x)+(4)(1)#
#6x + 4 = 12/2 x + 4#
#6x + 4 = 6x + 4#
Subtract #6x# from both sides
#6x + 4 - 6x= 6x + 4-6x#
#4=4#
Subtract #4# from both sides
#4-4=4-4#
#0=0#

All real numbers are solutions.