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Answer 1 · 2017-10-24T08:35:12

The maximum height it can reach is 19.6 m .

Initial velocity = #u# = 19.6 m/s
.
Final velocity when it reaches some height (from where it starts falling downwards will be zero,

#v = 0# m/s

as it is going upwards, acceleration # a= -g = -9.8 # m/ #s^2#

To know the distance covered by the object, we will use the equation of motion:

# s = (v^2 - u^2)/ (2a)#

#s = (0^2 - 19.6^2)/ (2xx -9.8)#

#s = cancel- (19.6xxcancel19.6)/(cancel-cancel19.6#

#s = 19.6 #m

# therefore# The maximum height it can reach is 19.6 m .