Question

What is the standard form of `y= 2(7/5x + 14)^2 - 1`?

Answer 1

The expression can be standardized as:
`y = 98/25x² + 392/5x + 391`

Explanation:

To put the expression in the standard form, apply the power on the parentheses:

`y = 2 * (7/5 x + 14)^² - 1`
`y = 2 * (49/25x²+ 2 * (7/5x) * 14 + 196) - 1`
`y = 2 * (49/25x²+ 196/5x + 196) -1`

Now, multiply the inside of the parentheses by 2 (the number outside multiplying it):

`y = 98/25x² + 392/5x + 392 - 1 = 98/25x² + 392/5x + 391`