How do you evaluate #( k ^ { 6} - 7k ^ { 5} + 4k ^ { 4} ) \div k ^ { 2}#?

1 Answer
Oct 24, 2017

See a solution process below:

Explanation:

First, we can rewrite this expression as:

#(k^6 - 7k^5 - 4k^4)/k^2 => k^6/k^2 - (7k^5)/k^2 - (4k^4)/k^2#

Next, we can use this rule of exponents to eliminate the fractions:

#x^color(red)(a)/x^color(blue)(b) = x^(color(red)(a)-color(blue)(b))#

#k^(6-2) - 7k^(5-2) - 4k^(4-2) =>#

#k^4 - 7k^3 - 4k^2#