Question

What (i) MOLAR quantities, and (ii) masses with respect to each element exist in a `6.34*g` mass of ethanol?

Answer 1

Should it not be approx. `0.413*mol` of `"dihydrogen gas....."`?

Explanation:

We gots (I think) `6.34*g` of ethanol.....this represents a molar quantity of....

`(6.34*g)/(46.07*g*mol^-1)=0.138*mol` WITH RESPECT TO ETHANOL.

And there are thus `6xx0.138*mol` WITH RESPECT TO `"hydrogen atoms"`.

And, with respect hydrogen, there is a mass of `0.138*molxx6xx1.00794*g*mol^-1=0.835*g` hydrogen.....

We would determine the mass of carbon and hydrogen in precisely the same way.....

Of course we would not make ethanol from its elements, but from the hydration of ethylene.....

`H_3C=CH_2stackrel(H^+"/"H_2O)rarrH_3C-CH_2OH`....