First, divide each side of the inequality by #color(red)(3)# to eliminate the parenthesis while keeping the inequality balanced:
#(3(3x + 2))/color(red)(3) < -3/color(red)(3)#
#(color(red)(cancel(color(black)(3)))(3x + 2))/cancel(color(red)(3)) < -1#
#3x + 2 < -1#
Next, subtract #color(red)(2)# from each side of the inequality to isolate the #x# term while keeping the inequality balanced:
#3x + 2 - color(red)(2) < -1 - color(red)(2)#
#3x + 0 < -3#
#3x < -3#
Now, divide each side of the inequality by #color(red)(3)# to solve for #x# while keeping the inequality balanced:
#(3x)/color(red)(3) < -3/color(red)(3)#
#(color(red)(cancel(color(black)(3)))x)/cancel(color(red)(3)) < -1#
#x < -1#
